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  1.  
  2. import re
  3.  
  4.  
  5. corpus = []
  6.  
  7. x = "12/1/2017"
  8. if re.search(r'\d{2}/\d{2}/\d{4}',x): ### for mm/dd/yyyy
  9. y= re.findall(r'\d{2}/\d{2}/\d{4}',x)
  10. corpus.append(y)
  11. elif re.search(r'\d{2}/\d/\d{4}',x): ### for mm/d/yyyy
  12. y= re.findall(r'\d{2}/\d/\d{4}',x)
  13. corpus.append(y)
  14. elif re.search(r'\d/\d{2}/\d{4}',x): ### for m/dd/yyyy
  15. y= re.findall(r'\d/\d{2}/\d{4}',x)
  16. corpus.append(y)
  17. elif re.search(r'\d/\d/\d{4}',x): ### for m/d/yyyy
  18. y= re.findall(r'\d/\d/\d{4}',x)
  19. corpus.append(y)
  20. else: ### empty cells or says nan
  21. y=["00/00/0000"]
  22. corpus.append(y)
  23.  
  24. print(corpus)
Success #stdin #stdout 0.02s 27712KB
stdin
Standard input is empty
stdout
[['12/1/2017']]