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  1. #include <iostream>
  2. using namespace std;
  3.  
  4. void merge(int arr[], int p, int q, int r) {
  5.  
  6.   int n1 = q - p + 1;
  7.   int n2 = r - q;
  8.  
  9.   int L[n1], M[n2];
  10.  
  11.   for (int i = 0; i < n1; i++)
  12.     L[i] = arr[p + i];
  13.   for (int j = 0; j < n2; j++)
  14.     M[j] = arr[q + 1 + j];
  15.  
  16.   int i, j, k;
  17.   i = 0;
  18.   j = 0;
  19.   k = p;
  20.  
  21.   while (i < n1 && j < n2) {
  22.     if (L[i] <= M[j]) {
  23.       arr[k] = L[i];
  24.       i++;
  25.     } else {
  26.       arr[k] = M[j];
  27.       j++;
  28.     }
  29.     k++;
  30.   }
  31.  
  32.   while (i < n1) {
  33.     arr[k] = L[i];
  34.     i++;
  35.     k++;
  36.   }
  37.  
  38.   while (j < n2) {
  39.     arr[k] = M[j];
  40.     j++;
  41.     k++;
  42.   }
  43. }
  44. void mergeSort(int arr[], int l, int r) {
  45.   if (l < r) {
  46.     int m = l + (r - l) / 2;
  47.  
  48.     mergeSort(arr, l, m);
  49.     mergeSort(arr, m + 1, r);
  50.     merge(arr, l, m, r);
  51.   }
  52. }
  53.  
  54. void printArray(int arr[], int size) {
  55.   for (int i = 0; i < size; i++)
  56.     cout << arr[i] << " ";
  57.   cout << endl;
  58. }
  59.  
  60. int main() {
  61.   int arr[] = {6, 5, 12, 10, 9, 1};
  62.   int size = sizeof(arr) / sizeof(arr[0]);
  63.  
  64.   mergeSort(arr, 0, size - 1);
  65.  
  66.   cout << "Sorted array: \n";
  67.   printArray(arr, size);
  68.   return 0;
  69. }
  70.  
Success #stdin #stdout 0s 4232KB
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stdin
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Standard input is empty
stdout
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Sorted array: 
1 5 6 9 10 12
https://ideone.com/URSm5l
language:
C++ (gcc 8.3)
created:
3 years ago
visibility:
public

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