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  1. options = ["arish1", "arish2", "ARISH3", "arish 2", "arish"]
  2. choices = ["Arish"]
  3. final_choice = options.grep(/\A(?:#{Regexp.union(choices).source})\z/i)
  4. p final_choice
  5.  
  6. #Output:  ["arish1", "arish2", "ARISH3", "arish 2", "arish"]
Success #stdin #stdout 0.01s 6428KB
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Standard input is empty
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["arish"]
https://ideone.com/UGtONx
language:
Ruby (ruby 2.5.5)
created:
3 years ago
visibility:
public

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