fork download
  1. #include <bits/stdc++.h>
  2. #include <chrono>
  3. using namespace std;
  4. using namespace chrono;
  5. // "AJEET JAIN"----"JAI JINENDRA"
  6. /* "णमो अरिहंताणं",
  7.   "णमो सिद्धाणं",
  8.   "णमो आयरियाणं",
  9.   "णमो उवज्झायाणं",
  10.   "णमो लोए सव्वसाहूणं",
  11.   "",
  12.   "एसो पंच नमोक्कारो, सव्व पावप्पणासणो",
  13.   "मंगलाणं च सव्वेसिं, पडमं हवै मंगलं", */
  14.  
  15.  
  16. // Aliases to op
  17. using ll = long long;
  18. using ull = unsigned long long;
  19. using ld = double;
  20. using vll = vector<ll>;
  21.  
  22.  
  23. // Constants
  24. constexpr ll INF = 4e18;
  25. constexpr ld EPS = 1e-9;
  26. constexpr ll MOD = 1e9 + 7;
  27.  
  28.  
  29.  
  30. // Macros
  31. #define F first
  32. #define S second
  33. #define all(x) begin(x), end(x)
  34. #define allr(x) rbegin(x), rend(x)
  35. #define py cout<<"YES\n";
  36. #define pn cout<<"NO\n";
  37. #define forn(i,n) for(int i=0;i<n;i++)
  38. #define for1(i,n) for(int i=1;i<=n;i++)
  39.  
  40. // #define insert push_back
  41. #define pb push_back
  42. #define MP make_pair
  43. #define endl '\n'
  44.  
  45. /*
  46.   remove substring or subarray ---> try to think about sliding w
  47.  
  48.   */
  49.  
  50. /*
  51.  
  52.   Golden Rule
  53.  
  54.   1) problem is easy
  55.   2) proofs is easy
  56.   3) implementation is easy
  57.  
  58.   /*
  59.   ROUGH --
  60.  
  61.   */
  62.  
  63. ll ans(ll x){
  64. ll sum = 0;
  65. while(x != 0){
  66. sum += x%10;
  67. x = x/10;
  68. }
  69. return sum;
  70. }
  71.  
  72. void AJNJ(){
  73. ll n;
  74. cin >> n;
  75. vector<ll> v(n);
  76. vector<pair<ll , ll>> digit;
  77. map<ll , ll> freq;
  78. for(int i = 0 ; i < n ; i++){
  79. cin >> v[i];
  80. digit.push_back({ans(v[i]) , v[i]});
  81. freq[ans(v[i])]++;
  82. }
  83. map<ll , ll>mp;
  84. for(int i = 0 ; i < digit.size() ; i++){
  85. mp[digit[i].F] = max(digit[i].S , mp[digit[i].F]);
  86. }
  87. ll ans = INT_MIN;
  88. for(int i = 0 ; i < digit.size() ; i++){
  89. if(freq[digit[i].F] > 1){
  90. ans = max(ans , mp[digit[i].F]);
  91. }
  92. }
  93.  
  94. cout << ans << endl; /// T.C = O(10*N)
  95.  
  96. }
  97.  
  98.  
  99. int main(){
  100. ios::sync_with_stdio(0);
  101. cin.tie(0);
  102. cout.tie(0);
  103. int T = 1;
  104. cin>>T;
  105. auto start1 = high_resolution_clock::now();
  106. while(T--){
  107. AJNJ();
  108. }
  109. auto stop1 = high_resolution_clock::now();
  110. auto duration = duration_cast<microseconds>(stop1 - start1);
  111. cerr << "Time: " << duration . count() / 1000 << " ms" << endl;
  112.  
  113. return 0;
  114. }
Success #stdin #stdout #stderr 0.01s 5320KB
stdin
Standard input is empty
stdout
-2147483648
stderr
Time: 0 ms