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  1. import re
  2. p = re.compile(r'var\d+(?:(?!var\d).)*?secondVar', re.DOTALL)
  3. test_str = "var12.1\na\na\ndsa\n\n88\n123!!!\nsecondVar12.1\nvar12.1\na\na\ndsa\n\n88\n123!!!\nsecondVar12.1"
  4. print(p.findall(test_str))
Success #stdin #stdout 0.01s 7276KB
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stdin
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Standard input is empty
stdout
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['var12.1\na\na\ndsa\n\n88\n123!!!\nsecondVar', 'var12.1\na\na\ndsa\n\n88\n123!!!\nsecondVar']
https://ideone.com/TXzNJa
language:
Python (cpython 2.7.16)
created:
6 years ago
visibility:
secret

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