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  1. import re 
  2. l = ["42. blabla \n foo", "42 blabla \n foo", "422. blabla \n foo"]
  3. regex_header = re.compile(r"^\d+(?![.\d])")
  4. for s in l:
  5.     if (regex_header.search(s)):
  6.     	print(s)
Success #stdin #stdout 0.02s 27712KB
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stdin
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Standard input is empty
stdout
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42 blabla 
 foo
https://ideone.com/TQNKMj
language:
Python 3 (python  3.12)
created:
6 years ago
visibility:
secret

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