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  1. import numpy as np
  2.  
  3. def isin_seq(a,b):
  4.     # Look for the presence of b in a, while keeping the sequence
  5.     sidx = a.argsort()
  6.     idx = np.searchsorted(a,b,sorter=sidx)
  7.     idx[idx==len(a)] = 0
  8.     ssidx = sidx[idx]
  9.     return (np.diff(ssidx)==1).all() & (a[ssidx]==b).all()
  10.  
  11. haystack = np.array([1, 1, 2])
  12. needle = np.array([1, 2])
  13.  
  14. print(isin_seq(haystack, needle))
Success #stdin #stdout 0.19s 27236KB
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https://ideone.com/T1Sulw
language:
Python 3 (python  3.12)
created:
6 years ago
visibility:
public

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