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  1. #include <stdio.h>
  2. int total,ans,n,i;
  3. int main(){
  4. 	float r; scanf("%f",&r);
  5. 	n = ((r*1000 + 5) / 10);
  6. 	ans = 0;
  7. 	total = 36000;
  8. 	for (i = 1; i <= 36000; ++i){
  9. 		if((total%i) == 0 && (n%(total/i)) == 0){
  10. 			ans = i;
  11. 			break;
  12. 		}
  13. 	}
  14. 	printf("%d\n",ans);
  15. return 0;}
Success #stdin #stdout 0s 15232KB
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https://ideone.com/SdxmH5
language:
C++ (gcc 8.3)
created:
5 years ago
visibility:
secret

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