int op=0;
int sum0(int n,int* A) {
int i,j,k,v,Aij,Ajk,Aki,s=0; op=0;
for(i=0;i<n;i++) {
for(j=0;j<n;j++) {
Aij=A[i*n+j];op++;
for(k=0;k<n;k++) {
Ajk=A[j*n+k]; Aki=A[k*n+i]; op+=2;
v=Ajk<Aki?Ajk:Aki;
v=Aij<v?Aij:v;
s=s+v;
}
}
}
return s;
}
int sum1(int n,int* A) {
int i,j,k,Cij,Aij,Ajk,Aki,s=0; op=0;
for(i=0;i<n;i++) {
for(j=0;j<n;j++) { if (i==j) continue;
Aij=A[i*n+j]; op++; if (Aij<=0) continue;
for(Cij=k=0;k<n;k++) {
Ajk=A[j*n+k]; op++; if (Aij>Ajk) continue;
Aki=A[k*n+i]; op++; if (Aij>Aki) continue;
if (Aij<Ajk && Aij<Aki) Cij+=3;
else if (Aij==Ajk && Aij<Aki) Cij+=2;
else if (Aij<=Ajk && Aij==Aki) Cij++;
}
s+=Aij*Cij;
}
}
return s;
}
#include <time.h>
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char const *argv[]) {
enum { n=10 };
int i,j,v,A[n*n];
for(i=0;i<n;i++) {
for(j=0;j<n;j++) {
A[i*n+j]=i==j?0 : v;
}
}
for(i=0;i<n;i++) {
for(j
=0;j
<n
;j
++) printf("%4d",A
[i
*n
+j
]); }
return 0;
}
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