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  1. #include<stdio.h>
  2. #include<math.h>
  3. int main()
  4. {
  5.     double a,b,c;
  6.     scanf("%lf %lf %lf",&a,&b,&c);
  7.     if (a==0)
  8.     {
  9.     	printf("Value of a must be non zero\n");
  10.     	return 0;
  11.     }
  12.     double d = (b*b)-(4*a*c);
  13.  
  14.     if (d<0){
  15.     	double imag = sqrt(-d)/(a+a);
  16.     	double real = -b/(a+a);
  17.         printf("Complex solution\n");
  18.         printf("R1 = %.2f + j * %.2f\n",real, imag);
  19.         printf("R2 = %.2f - j * %.2f\n",real, imag);
  20.  
  21.     }
  22.     else
  23.     {
  24.     	double x1 = (-b + sqrt(d))/(a+a);
  25.     	double x2 = (-b - sqrt(d))/(a+a);
  26.         printf("R1 = %.2f\n",x1);
  27.         printf("R2 = %.2f\n",x2);
  28.     }
  29.     return 0;
  30. }
Success #stdin #stdout 0s 4496KB
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stdin
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stdout
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Complex solution
R1 = -1.50 + j * 1.66
R2 = -1.50 - j * 1.66
https://ideone.com/R7UwhG
language:
C99 (gcc 8.3)
created:
5 years ago
visibility:
public

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