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  1. #include <stdio.h>
  2.  
  3. void countOddEven(int *arr, int size, int *oddCount, int *evenCount) {
  4.     *oddCount = 0;
  5.     *evenCount = 0;
  6.  
  7.     for (int i = 0; i < size; i++) {
  8.         if (*(arr + i) % 2 == 0) {
  9.             (*evenCount)++;
  10.         } else {
  11.             (*oddCount)++;
  12.         }
  13.     }
  14. }
  15.  
  16. int main() {
  17.     int arr[] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
  18.     int size = sizeof(arr) / sizeof(arr[0]);
  19.     int oddCount, evenCount;
  20.  
  21.     countOddEven(arr, size, &oddCount, &evenCount);
  22.  
  23.     printf("Number of odd numbers: %d\n", oddCount);
  24.     printf("Number of even numbers: %d\n", evenCount);
  25.  
  26.     return 0;
  27. }
Success #stdin #stdout 0s 5388KB
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stdin
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45
stdout
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Number of odd numbers: 5
Number of even numbers: 4
https://ideone.com/QzgaTK
language:
C (gcc 8.3)
created:
2 years ago
visibility:
public

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