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  1. #!/bin/bash
  2.  
  3. bash -c 'echo first "$1"; echo second "$2"; echo third "$3"; echo all "$@"; printf ">>%s<<\n" "$@" | nl' one "two three" four "five
  4. six
  5. seven" eight nine
Success #stdin #stdout 0s 4400KB
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stdin
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Standard input is empty
stdout
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first two three
second four
third five
six
seven
all two three four five
six
seven eight nine
     1	>>two three<<
     2	>>four<<
     3	>>five
     4	six
     5	seven<<
     6	>>eight<<
     7	>>nine<<
https://ideone.com/Qbo6GO
https://stackoverflow.com/questions/64820632/how-to-pass-all-arguments-to-a-script-called-by-bin-bash
language:
Bash (bash 5.0.3)
created:
5 years ago
visibility:
secret

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