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  1. #include <iostream>
  2. using namespace std;
  3.  
  4. int main() {
  5. 	// your code goes here
  6. 	int n;
  7. 	scanf("%d",&n);
  8. 	if(n>=1000)n=50000+(n-1000)*100;
  9. 	else n = ((n/100)*5)*n;
  10. 	printf("%d.%02d",n/100,n%100);
  11. 	return 0;
  12. }
Success #stdin #stdout 0.01s 5464KB
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https://ideone.com/QJuXvM
language:
C++14 (gcc 8.3)
created:
1 year ago
visibility:
public

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