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  1. import re
  2.  
  3. text = '0412020982012'
  4. rg = r'20[1-2]\d+'
  5. years = re.compile("(%s)" % (rg)).findall(text)
  6.  
  7. print(years)
Success #stdin #stdout 0.01s 27712KB
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['2020982012']
https://ideone.com/QGS8ZW
language:
Python 3 (python  3.9.5)
created:
4 years ago
visibility:
public

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