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  1. /********************Java Code************/
  2.  
  3. /******************Main.java****************/
  4. import java.util.Arrays;
  5.  
  6. public class Main {
  7. 	public static void main (String args[]) {
  8. 		int numbers[]= {1,5,-9,12,-3,89, 18,23,4,-6};
  9. 		// Find minimum (lowest) value in array using loop
  10. 		System.out.println("Minimum Value = " + getMinValue(numbers));
  11. 		// Find maximum (largest) value in array using loop
  12. 		System.out.println("Maximum Value = " + getMaxValue(numbers));
  13.  
  14.  
  15.  
  16. 		// ADD CODE TO CALL getAvgValue AND PRINT THE AVERAGE
  17. 		// Don't forget to call the avg method below ... call it just like
  18. 		// the two methods above ...
  19.  
  20. 		System.out.println("Average Value = " + getAvgValue(numbers));
  21.  
  22. 		// Add any challenge method calls here ....
  23.  
  24. 		// ADD CODE TO SORT THE NUMBERS IN THE ARRAY, PRINT THE SORTED ARRAY
  25. 		Arrays.sort(numbers);
  26.  
  27. 		System.out.println("Array after sorting");
  28. 		for (int i = 0; i < numbers.length; i++) {
  29. 			System.out.print(numbers[i]+ " ");
  30. 		}
  31. 		// Use the built-in array sort method on the array
  32. 		// ... then add a loop here (no need to call a method) to print
  33. 		// the now sorted array. See our lecture notes for examples.
  34. 		// using sorted array calling median
  35. 		System.out.println("\nMedian Value = " + getMedian(numbers));
  36.  
  37. 	}
  38.  
  39. 	// Find maximum (largest) value in array using loop
  40.  
  41. 	public static int getMaxValue(int[] numbers) {
  42.  
  43. 		int maxValue = numbers[0]; // set the first array element (index of 0) as the max
  44.  
  45. 		// ... remember that arrays start with an index of 0   
  46. 		// ADD CODE TO ADD A LOOP, CHECK EACH ARRAY ELEMENT
  47. 		// AGAINST THE CURRENT maxValue (USE AN IF STATEMENT)   
  48.  
  49. 		// The key is to use a loop with the length property of the array
  50. 		// to access and check every element after the first element. The if statement
  51. 		// each time will check the current max value against the current
  52. 		// array value. At the end of the loop, maxValue will contain
  53. 		// the largest number in the array.
  54.  
  55. 		// Access each array element starting with the second element (i = 1, not 0)
  56. 		try {
  57. 			for (int i = 1; i < numbers.length; i++) {   
  58. 				if (numbers[i] > maxValue) { // is the current element greater than the current max value?
  59. 					maxValue = numbers[i]; // the current element is now the max value
  60. 				} // end if
  61. 			} // end for
  62. 		} catch (ArrayIndexOutOfBoundsException e) { //catching ArrayIndexOutOfBoundsException exception
  63. 			System.out.println("Array Index out of bound exception"+e.getMessage());
  64. 		}
  65. 		return maxValue; // return the largest array element value
  66.  
  67. 	} // getMaxValue
  68.  
  69. 	// Find minimum (lowest) value in array using loop
  70.  
  71. 	public static int getMinValue(int[] numbers) {
  72.  
  73. 		int minValue = numbers[0];
  74.  
  75. 		// ADD CODE TO ADD A LOOP, CHECK EACH ARRAY ELEMENT
  76. 		// AGAINST THE CURRENT minValue (USE AN IF STATEMENT)
  77.  
  78. 		// Hint: This is just like the for loop in the max function above, just revise to check for min value instead of max value
  79. 		try {
  80. 			for (int i = 1; i < numbers.length; i++) {   
  81. 				if (numbers[i] < minValue) { // is the current element less than the current min value?
  82. 					minValue = numbers[i]; // the current element is now the min value
  83. 				} // end if
  84. 			} // end for
  85.  
  86. 		} catch (ArrayIndexOutOfBoundsException e) {  //catching ArrayIndexOutOfBoundsException exception
  87. 			System.out.println("Array Index out of bound exception"+e.getMessage());
  88. 		}
  89.  
  90. 		return minValue;
  91.  
  92. 	} // getMinValue
  93.  
  94.  
  95. 	// Find the average of an array of integers
  96.  
  97. 	public static double getAvgValue(int[] numbers) {
  98.  
  99. 		// ADD CODE TO SET UP NEEDED VARIABLES, ONE TO SUM ALL ARRAY ELEMENT VALUES, AND
  100. 		// AND ANOTHER ONE, average, TO BE USED TO CALCULATE THE AVERAGE OF ALL ARRAY ELEMENT VALUES
  101.  
  102. 		double average = 0;
  103. 		double sum = 0;
  104.  
  105. 		// ADD CODE TO ADD A LOOP TO COMPUTE A RUNNING TOTAL OF ALL ARRAY ELEMENTS
  106.  
  107. 		// use a loop like in the max function, but instead of an if, add the current
  108. 		// array element value to sum. This will keep a running total as each element value is added
  109. 		// to sum as it is accessed in the loop: sum = sum + numbers[i] ;
  110.  
  111. 		// ADD CODE TO COMPUTE THE AVERAGE
  112.  
  113. 		// The average just takes the sum variable and divides it by the total number of array items (i.e., numbers.length)
  114.  
  115. 		try {
  116. 			for (int i = 1; i < numbers.length; i++) {   
  117. 				sum = sum + numbers[i]; // add the current element value into the sum
  118. 			} // end for
  119.  
  120. 			average = sum/numbers.length; //to find average divide total sum with total elements
  121. 		} catch (ArithmeticException e) {  //catching ArithmeticException exception
  122. 			System.out.println("Dividing by zero exception");
  123. 		} catch (ArrayIndexOutOfBoundsException e) {  //catching ArrayIndexOutOfBoundsException exception
  124. 			System.out.println("Array Index out of bound exception"+e.getMessage());
  125. 		}
  126.  
  127. 		return average;
  128.  
  129. 	} // getAvgValue
  130.  
  131. 	// Add any Challenge methods here ...
  132.  
  133. 	public static double getMedian(int[] numbers) {
  134. 		//this will hold median value
  135. 		double median = 0;
  136. 		//assuming numbers array will come in sorted order then only this method works
  137. 		try {
  138. 			//middle index of array
  139. 			int middleIndex = numbers.length/2;
  140.  
  141. 			if(numbers.length% 2 == 1) { //checking if length of array is odd
  142. 				//set median as middleIndex value
  143. 				median = numbers[middleIndex];
  144. 			} else { //if length of array is even
  145. 				//set median as sum of middle and middle + 1 index divide by 2
  146. 				median = ((numbers[middleIndex] + numbers[middleIndex + 1]) /2);
  147. 			}
  148. 		} catch (ArithmeticException e) { //catching ArithmeticException exception
  149. 			System.out.println("Dividing by zero exception");
  150. 		} catch (ArrayIndexOutOfBoundsException e) { //catching ArrayIndexOutOfBoundsException exception
  151. 			System.out.println("Array Index out of bound exception"+e.getMessage());
  152. 		}
  153.  
  154. 		return median;
  155. 	}
  156.  
  157. } // Main Class
  158.  
Success #stdin #stdout 0.15s 52612KB
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Minimum Value = -9
Maximum Value = 89
Average Value = 13.3
Array after sorting
-9 -6 -3 1 4 5 12 18 23 89 
Median Value = 8.0
https://ideone.com/Pb0hat
language:
Java (HotSpot 12)
created:
75 days ago
visibility:
public

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