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  1. #include <iostream>
  2. using namespace std;
  3.  
  4. int main() {
  5. 	int n;
  6. 	double k = 1;
  7. 	while ( cin >> n ) {
  8. 		for ( int i = 366 - n; i <= 365; i++ ) {
  9. 			k = k * i;
  10. 			k = k / 365;
  11. 		}
  12. 		cout << fixed;
  13. 		cout.precision(8);
  14. 		cout << 100 * ( 1 - k ) << "%" << endl;
  15. 		k=1;
  16. 	}
  17. 	return 0;
  18. }
Success #stdin #stdout 0s 4368KB
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stdin
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399
stdout
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100.00000000%
https://ideone.com/PRY2vp
language:
C++ (gcc 8.3)
created:
6 years ago
visibility:
public

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