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  1. #include <stdio.h>
  2.  
  3. int main() {
  4. 	int n,ans = 1000001; 
  5. 	scanf("%d",&n);
  6. 	int a[1003]= {};
  7. 	int luu[1000003] = {};
  8. 	for (int i = 0; i<n; ++i) {
  9. 		scanf("%d",&a[i]);
  10. 		++luu[a[i]];
  11. 	}
  12. 	for (int i = 0; i<sizeof(luu)/sizeof(luu[0]); ++i) {
  13. 		if (luu[i]!=0) {
  14. 			ans = i;
  15. 			break;
  16. 		}
  17. 	}
  18. 	printf("%d %d",ans,luu[ans]);
  19. }
Success #stdin #stdout 0s 5488KB
comments (?)
stdin 
7
8 15 2 4 2 2 5
stdout 
2 3
https://ideone.com/OGVCDr
language:
C (gcc 8.3)
created:
8 hours ago
visibility:
public

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