//面试考题3 吕德勤
/*小王跟小李在玩一个猜数字游戏。首先小王选一个1到10的整数。然后，小李猜小王选了什
么数字，小王说小李猜的数字正确（“correct”）太大（“too high”）或者太小（“too low”），这
样重复直到“correct”为止。小李怀疑小王作弊，也就是说小王给的correct/too high/too low反
映有矛盾。
标准输入(stdin)有N场游戏的记录（N≥0），每两行表示小李的答案（1到10）跟小王的回复。
每场游戏最后都是“correct”。输入最后有一行“0”表示输入完毕。
提交的标准C或C++程序需要为每场游戏作出判断，游戏记录从标准输入读入。如果小王绝对
是作弊了（也就是说小王的反映有矛盾），输出一行“yes”到标准输出(stdout)，否则输出一行
“maybe”。*/
 
#include <iostream>
#include <string>
 
using namespace std;
 
int number[10] = { 0 };
int n;
const char tooHigh[10] = "too high";
const char tooLow[10] = "too low";
const char correct[10] = "correct";
 
int strcmp(const char *str1, const char *str2);
void doTooHigh(int x);
void doTooLow(int x);
void doCorrect(int x);
 
int main(void) {
	char reply[10];
	cin >> n;
	while (n != 0) {
		cin.getline(reply, 10);
		if (strcmp(reply, tooHigh) == 0)
			doTooHigh(n);
		else if (strcmp(reply, tooLow) == 0)
			doTooLow(n);
		else if (strcmp(reply, correct) == 0)
			doCorrect(n);
		cin >> n;
	}
 
	return 0;
}
 
void doTooHigh(int x) {
	for (int i = n; i <= 10; i++)
		number[i] = 1;
}
 
void doTooLow(int x) {
	for (int i = n; i > 0; i--)
		number[i] = 1;
}
 
void doCorrect(int x) {
	if (number[n] == 0)
		cout << "maybe";
	else cout << "yes";
	for (int i = 0; i <= 10; i++)
		number[i] = 0;
}

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MTAKdG9vIGhpZ2gKMwp0b28gbG93CjQKdG9vIGhpZ2gKMgpjb3JyZWN0CjUKdG9vIGxvdwo3CnRvbyBoaWdoCjYKY29ycmVjdAow

10
too high
3
too low
4
too high
2
correct
5
too low
7
too high
6
correct
0