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  1. #include<stdio.h>
  2. void f(int n, int p, int q, bool c){
  3.     if(n==0){
  4.         putchar(" *"[c]);
  5.         return;
  6.     }
  7.     int i=p%5;
  8.     int j=q%5;
  9.     f(n-1,p/5,q/5,c&&("0010000100111110101001010"[i*5+j]=='1'));
  10. }
  11. int main(){
  12.     int n,m;
  13.     scanf("%d",&n);
  14.     m=1;
  15.     for(int i=0;i<n;i++){
  16.         m*=5;
  17.     }
  18.     for(int i=0;i<m;i++,putchar(10))
  19.         for(int j=0;j<m;j++)
  20.             f(n,i,j,1);
  21. }
Success #stdin #stdout 0.01s 5320KB
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  *  
  *  
*****
 * * 
 * *
https://ideone.com/NZ4Iww
language:
C++14 (gcc 8.3)
created:
19 hours ago
visibility:
public

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