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  1. #include <stdio.h>
  2. int tas(int x,int y){
  3. 	return x+y;
  4. }
  5.  
  6. int jyo(int x){
  7. 	return x*x*x;
  8. }
  9.  
  10. int main(void) {
  11. 	// your code goes here
  12. 	int a,b;
  13. 	a=2;
  14. 	b=-3;
  15. 	printf("(%d+%d)^3=%d\n",a,b,jyo(tas(a,b)));
  16. 	return 0;
  17. }
  18.  
Success #stdin #stdout 0s 5320KB
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Standard input is empty
stdout
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(2+-3)^3=-1
https://ideone.com/NQqb5f
language:
C (gcc 8.3)
created:
4 days ago
visibility:
public

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