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  1. data_t=[[20,40,60],[88,44,22]]
  2. print("探索値は?")
  3. num = int(input())
  4. for i in range(len(data_t)):
  5.     for j in range(len(data_t[i])):
  6.         if num == data_t[i][j]:
  7.             print(f"{num}は{i+1}行目の左から{j+1}番目に存在")
  8.             break
  9.  
Success #stdin #stdout 0.04s 9816KB
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stdin
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22
stdout
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探索値は?
22は2行目の左から3番目に存在
https://ideone.com/NJVXfN
language:
Python 3 (python  3.9.5)
created:
363 days ago
visibility:
secret

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