section .data
    prompt1   db "Введите первое число: ", 0
    prompt2   db "Введите второе число: ", 0
    result    db "Результат: ", 0
    newline   db 0xA, 0xD, 0
    buffer    times 32 db 0
    N         equ 4          ; размер чисел в байтах
 
section .bss
    num1      resd 1
    num2      resd 1
    sum       resd 1
 
section .text
    global _start
 
; Процедура ввода числа (возвращает в EAX)
input_number:
    push ebx
    push ecx
    push edx
    push esi
 
    ; Вывод приглашения
    mov eax, 4
    mov ebx, 1
    mov edx, 21
    int 0x80
 
    ; Ввод строки
    mov eax, 3
    mov ebx, 0
    mov ecx, buffer
    mov edx, 32
    int 0x80
 
    ; Преобразование строки в число
    mov esi, buffer
    xor eax, eax
    xor ebx, ebx
    mov ecx, 10
    xor edx, edx        ; флаг знака
 
    ; Проверка на знак минус
    cmp byte [esi], '-'
    jne .parse_loop
    inc edx             ; установить флаг отрицательного
    inc esi             ; пропустить минус
 
.parse_loop:
    mov bl, [esi]
    cmp bl, 0xA         ; конец строки (LF)
    je .finish
    cmp bl, 0xD         ; конец строки (CR)
    je .finish
    cmp bl, '0'
    jb .finish
    cmp bl, '9'
    ja .finish
 
    sub bl, '0'
    imul ecx            ; eax = eax * 10
    add eax, ebx
    inc esi
    jmp .parse_loop
 
.finish:
    ; Применяем знак если нужно
    test edx, edx
    jz .done
    neg eax
 
.done:
    pop esi
    pop edx
    pop ecx
    pop ebx
    ret
 
; Процедура вывода числа из EAX
output_number:
    push eax
    push ebx
    push ecx
    push edx
    push esi
 
    mov esi, buffer + 31
    mov byte [esi], 0
    dec esi
    mov byte [esi], 0xA
    dec esi
 
    mov ecx, 10
    test eax, eax
    jns .positive
 
    ; Отрицательное число
    neg eax
    mov byte [esi], '-'
    dec esi
 
.positive:
    xor edx, edx
    div ecx
    add dl, '0'
    mov [esi], dl
    dec esi
    test eax, eax
    jnz .positive
 
    ; Вывод строки
    inc esi
    mov ecx, esi
    mov edx, buffer + 32
    sub edx, esi
 
    mov eax, 4
    mov ebx, 1
    int 0x80
 
    pop esi
    pop edx
    pop ecx
    pop ebx
    pop eax
    ret
 
_start:
    ; Ввод первого числа
    call input_number
    mov [num1], eax
 
    ; Ввод второго числа
    call input_number
    mov [num2], eax
 
    ; Сложение чисел
    mov eax, [num1]
    add eax, [num2]
    mov [sum], eax
 
    ; Вывод результата
    mov ecx, result
    mov edx, 11
    mov eax, 4
    mov ebx, 1
    int 0x80
 
    mov eax, [sum]
    call output_number
 
    ; Вывод новой строки
    mov ecx, newline
    mov edx, 2
    mov eax, 4
    mov ebx, 1
    int 0x80
 
    ; Завершение программы
    mov eax, 1
    xor ebx, ebx
    int 0x80

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