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  1. #include <iostream>
  2. #include <cmath>
  3. using namespace std;
  4.  
  5. int main() {
  6. 	double a, b, c, d, D;
  7. 	double x1,x2,x3;
  8. 	while(cin>>a>>b>>c>>d){
  9. 		D=b*b-4*a*(c-d);
  10. 		if(D>0)
  11. 		{
  12. 			x1=(-b-sqrt(D))/(2*a);
  13. 			x2=(-b+sqrt(D))/(2*a);
  14. 			cout<<x1<<", "<<x2<<"; ";
  15. 		}
  16. 		else
  17. 		{
  18. 			if(D==0)
  19. 			{
  20. 				x3=(-b)/(2*a);
  21. 				cout<<x3<<"; ";
  22. 			}
  23. 			else cout<<"нет корней"<<"; ";
  24. 		}
  25. 	}
  26. 	return 0;
  27. }
Success #stdin #stdout 0s 3472KB
comments (?)
stdin
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 1 1 -6 -2 1 -2 10 0 2 -0.5 2.2 0 5 0 -25 0
stdout
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-2.56155, 1.56155; нет корней; нет корней; -2.23607, 2.23607;
https://ideone.com/Mv2VzV
потоковая обработка(решения 2-уравнений, лаб)
language:
C++14 (gcc 8.3)
created:
7 years ago
visibility:
public

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