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  1. import re
  2. source = 'mystring/1234567890 hello world mystring/2345678901 hello'
  3. print(re.findall(r"(?<=\bmystring/)\d{10}(?!\S)",source))
Success #stdin #stdout 0.02s 27712KB
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stdin
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Standard input is empty
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['1234567890', '2345678901']
https://ideone.com/MtgISd
language:
Python 3 (python  3.12)
created:
6 years ago
visibility:
public

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