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  1. import re
  2. pattern = r'(?<!\d)\d{1,2}([.:/ -])(?:\d{1,2}|\w{3,})\1\d{4}(?!\d)'
  3. text = 'Aaaa 12-23-2019, bddd   29 10 2019 <===   1:2:2018'
  4. results = [x.group() for x in re.finditer(pattern, text)]
  5. print(results)
Success #stdin #stdout 0.02s 9580KB
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Standard input is empty
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['12-23-2019', '29 10 2019', '1:2:2018']
https://ideone.com/MEorit
language:
Python 3 (python  3.12)
created:
5 years ago
visibility:
secret

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