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  1.     <?php
  2.     $n=1;
  3.     if($n%2!==0 && $n>1){
  4.     for($i=1;$i<=$n;$i++){
  5.     	for($j=1;$j<=$n+2;$j++){
  6.     		echo "*";
  7.     	}
  8.     	echo "\n";
  9.     }
  10.     }else{
  11.     	echo "your no should be odd and ypur value should be greater than 1";
  12.     }
Success #stdin #stdout 0.03s 25796KB
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    your no should be odd and ypur value should be greater than 1
https://ideone.com/LxXW4f
language:
PHP (php 7.3.5)
created:
160 days ago
visibility:
public

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