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  1. #include <bits/stdc++.h>
  2. using namespace std;
  3.  
  4. #define fast_io ios::sync_with_stdio(0); cin.tie(0); cout.tie(0)
  5.  
  6. #define int long long
  7. #define pb push_back
  8. #define ff first
  9. #define ss second
  10. #define all(x) (x).begin(), (x).end()
  11. #define rall(x) (x).rbegin(), (x).rend()
  12. #define sz(x) ((int)(x).size())
  13. #define endl '\n'
  14. #define yes cout << "yes\n"
  15. #define no cout << "no\n"
  16.  
  17. #define rep(i,a,b) for(int i=a;i<b;++i)
  18. #define per(i,a,b) for(int i=b-1;i>=a;--i)
  19. #define each(x, a) for (auto& x : a)
  20.  
  21. const int INF = 1e18;
  22. const int MOD = 1e9+7;
  23. const int N = 2e5 + 5;
  24.  
  25. int gcd(int a, int b) { return b == 0 ? a : gcd(b, a % b); }
  26. int lcm(int a, int b) { return (a / gcd(a, b)) * b; }
  27.  
  28. int power(int a, int b, int m = MOD) {
  29.     int res = 1;
  30.     while (b > 0) {
  31.         if (b & 1) res = res * a % m;
  32.         a = a * a % m;
  33.         b >>= 1;
  34.     }
  35.     return res;
  36. }
  37.  
  38. int modinv(int a, int m = MOD) {
  39.     return power(a, m - 2, m);
  40. }
  41.  
  42. // Check function: can we generate the multiset 'positive_b' using max length 'x',
  43. // with a total of 'n' operations?
  44. bool check(int x, int n, const vector<int>& positive_b) {
  45.     if (x == 0) return false;
  46.     int total_required_ops = 0;
  47.  
  48.     // R(x) = Sum of ceil(b_i / x) for all positive elements b_i
  49.     each(val, positive_b) {
  50.         // ceil(val / x) = (val + x - 1) / x
  51.         total_required_ops += (val + x - 1) / x;
  52.     }
  53.  
  54.     // The required number of segments must be less than or equal to the total available operations (n).
  55.     return total_required_ops <= n;
  56. }
  57.  
  58. void solve() {
  59.     int n;
  60.     cin >> n;
  61.     vector<int> b(n);
  62.     vector<int> positive_b;
  63.     int sum_b = 0;
  64.  
  65.     rep(i, 0, n) {
  66.         cin >> b[i];
  67.         sum_b += b[i];
  68.         if (b[i] > 0) {
  69.             positive_b.pb(b[i]);
  70.         }
  71.     }
  72.  
  73.     // Special Case: If Sum(b_i) == n, then all n operations MUST have length 1.
  74.     // Length (l, r) must be 1. Max length x=1.
  75.     if (sum_b == n) {
  76.         cout << 1 << endl;
  77.         return;
  78.     }
  79.  
  80.     // General Case (Binary Search): Find the maximum length x such that the density constraints are met.
  81.     int low = 1;
  82.     int high = n;
  83.     int ans = 0;
  84.  
  85.     while (low <= high) {
  86.         int mid = low + (high - low) / 2;
  87.         if (check(mid, n, positive_b)) {
  88.             ans = mid;
  89.             low = mid + 1; // Try for a larger length
  90.         } else {
  91.             high = mid - 1; // Must use a smaller length
  92.         }
  93.     }
  94.  
  95.     cout << ans << endl;
  96. }
  97.  
  98. int32_t main() {
  99.     fast_io;
  100.  
  101.     int t;
  102.     cin >> t;
  103.     while (t--) {
  104.         solve();
  105.     }
  106.  
  107.     return 0;
  108. }
Success #stdin #stdout 0.01s 5308KB
comments (?)
stdin 
3
5
0 5 1 0 1
3
3 2 1
5
1 1 1 1 1
stdout 
5
0
1
https://ideone.com/LlIKwB
language:
C++ (gcc 8.3)
created:
9 days ago
visibility:
public

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