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  1. # include <iostream>
  2. using namespace std;
  3. void matpow(long double *m[],long double p)
  4.   {
  5.    if(p>1)
  6.     {matpow(m,p/2);
  7.      int i,j,k;
  8.      long double *g[2];
  9.      g[0]=new long double[2];
  10.      g[1]=new long double[2];
  11.      g[0][0]=g[0][1]=g[1][0]=g[1][1]=0;
  12.      for(i=0;i<2;++i)
  13.       for(j=0;j<2;++j)
  14.        for(k=0;k<2;++k)
  15.         g[i][j]+=(m[i][k]*m[k][j]);
  16.      if(p%2==1)
  17.       {m[0][0]=g[0][1];
  18.        m[0][1]=g[0][0]+g[0][1];
  19.        m[1][0]=g[1][1];
  20.        m[1][1]=g[1][0]+g[1][1];
  21.       }
  22.      else
  23.       {m[0][0]=g[0][0];
  24.        m[0][1]=g[0][1];
  25.        m[1][0]=g[1][0];
  26.        m[1][1]=g[1][1];
  27.  
  28.     }
  29.    }
  30. }
  31. int main()
  32.   {
  33.    long double *m[2],t,i,a,b,n,sum;
  34.    cin>>t;
  35.    for(i=0;i<t;++i)
  36.     {
  37.      cin >>n;
  38.      if(n==1)
  39.       cout <<"0\n";
  40.      else
  41.       if(n==2)
  42.        cout <<"1\n";
  43.       else
  44.        {
  45.         m[0]=new long double[2];m[1]=new long double[2]; m[0][0]=0;m[0][1]=m[1][1]=1;m[1][0]=2;
  46. matpow(m,n-2);
  47. printf("%.0Lf\n",m[1][1]);}}}
  48.  
Compilation error #stdin compilation error #stdout 0s 0KB
comments (?)
stdin
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6
1
2
3
4
5
999
compilation info 
prog.cpp: In function ‘void matpow(long double**, long double)’:
prog.cpp:16: error: invalid operands of types ‘long double’ and ‘int’ to binary ‘operator%’
prog.cpp: In function ‘int main()’:
prog.cpp:33: warning: unused variable ‘a’
prog.cpp:33: warning: unused variable ‘b’
prog.cpp:33: warning: unused variable ‘sum’
stdout
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Standard output is empty
https://ideone.com/LNTtV
language:
C++ (gcc 8.3)
created:
13 years ago
visibility:
public

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