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  1. import re
  2. a = 'A000AA'
  3. pattern = r'[ABCEHKMOPTXY]\d{3}[ABCEHKMOPTXY]{2}'
  4. print( bool(re.fullmatch( pattern, a)) )
  5.  
Success #stdin #stdout 0.02s 9652KB
stdin
Standard input is empty
stdout
True