#include <iostream>
#include <algorithm>
 
using namespace std;
 
pair<int, int> p[2503];
 
int women[501][501], men[501][501];         /// is women ke liye ye men kitna pe hai?
 
bool cmp(pair<int, int>& p1, pair<int, int>& p2){
    int x = women[p1.second][p1.first], y = men[p1.first][p1.second], x1 = women[p2.second][p2.first], y1 = men[p2.first][p2.second];
    if(x > y) swap(x, y);
    if(x1 > y1) swap(x1, y1);
    if(y <= y1) return 1;
    return 0;
}
 
void build(int n){
    int cnt = 0;
    for(int j = 1; j <= n; j++)
        for(int k = 1; k <= n; k++)
            p[cnt++] = make_pair(j, k);
}
 
int main(){
    int t;
    cin >> t;
    while(t--){
        int n;
        cin >> n;
        for(int j = 0; j < n; j++){
            int ind;
            cin >> ind;
            for(int k = 1; k <= n; k++){
                int pos;
                cin >> pos;
                women[ind][pos] = k;
            }
        }
 
        for(int j = 0; j < n; j++){
            int ind;
            cin >> ind;
            for(int k = 1; k <= n; k++){
                int pos;
                cin >> pos;
                men[ind][pos] = k;
                //if(k == n) cout << "here!\n";
            }
        }
        //cout << "here!\n";
        build(n);
        sort(p, p+n*n, cmp);
 
        int already1[501] = {0}, already2[501] = {0};
        for(int j = 0; j < n*n; j++)
            if(!already1[p[j].first] && !already2[p[j].second]){
                already1[p[j].first] = already2[p[j].second] = 1;
                cout << p[j].first << " " << p[j].second << endl;
            }
    }
    return 0;
}
 

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4
1 4 3 1 2
2 2 1 3 4
3 1 3 4 2
4 4 3 1 2
1 3 2 4 1
2 2 3 1 4
3 3 1 2 4
4 3 2 4 1
7
1 3 4 2 1 6 7 5
2 6 4 2 3 5 1 7
3 6 3 5 7 2 4 1
4 1 6 3 2 4 7 5
5 1 6 5 3 4 7 2
6 1 7 3 4 5 6 2
7 5 6 2 4 3 7 1
1 4 5 3 7 2 6 1
2 5 6 4 7 3 2 1
3 1 6 5 4 3 7 2
4 3 5 6 7 2 4 1
5 1 7 6 4 3 5 2
6 6 3 7 5 2 4 1
7 1 7 4 2 6 5 3