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  1. #include<bits/stdc++.h>
  2. using namespace std;
  3. #define endl '\n'
  4. #define int long long int
  5. const int MOD = 1000000007;
  6. const int MOD2 = 998244353;
  7. const int INF = LLONG_MAX / 2;
  8. const int MAXN = 100000;
  9. int primes[1000000];
  10.  
  11. /*void seive() {
  12.   fill(primes, primes + 1000000, 1);
  13.   primes[0] = primes[1] = 0;
  14.   for (int i = 2; i * i < 1000000; i++) {
  15.   if (primes[i]) {
  16.   for (int j = i * i; j < 1000000; j += i) {
  17.   primes[j] = 0;
  18.   }
  19.   }
  20.   }
  21. }
  22.  
  23. bool isPrime(int n) {
  24.   if (n <= 1) return false;
  25.   for (int i = 2; i * i <= n; i++) {
  26.   if (n % i == 0) return false;
  27.   }
  28.   return true;
  29. }
  30.  
  31. int gcd(int a, int b) {
  32.   if (a == 0) return b;
  33.   return gcd(b % a, a);
  34. }*/
  35.  
  36. int power(int a, int b, int mod) {
  37. int res = 1;
  38. a %= mod;
  39. while (b > 0) {
  40. if (b & 1) res = res * a % mod;
  41. a = a * a % mod;
  42. b >>= 1;
  43. }
  44. return res;
  45. }
  46.  
  47. // nCr % MOD for n < MOD
  48. int nCrModP(int n, int r) {
  49. if (r > n) return 0;
  50. if (r == 0 || r == n) return 1;
  51.  
  52. int numerator = 1, denominator = 1;
  53. for (int i = 0; i < r; i++) {
  54. numerator = (numerator * (n - i)) % MOD;
  55. denominator = (denominator * (i + 1)) % MOD;
  56. }
  57. return (numerator * power(denominator, MOD - 2, MOD)) % MOD;
  58. }
  59.  
  60. // Lucas's Theorem
  61. int lucas(int n, int r) {
  62. if (r == 0) return 1;
  63. return (lucas(n / MOD, r / MOD) * nCrModP(n % MOD, r % MOD)) % MOD;
  64. }
  65. void solve() {
  66. string s;
  67. cin>>s;
  68. int n = s.size();
  69. map<char,set<int>>mp;
  70. for(int i = 0 ; i<n ; i++){
  71. mp[s[i]].insert(i);
  72. }
  73. int q;
  74. cin>>q;
  75. vector<int>ans;
  76. for(int i = 0 ; i<q ; i++){
  77. int a,b,c;
  78. cin>>a>>b>>c;
  79. if(a==1){
  80. char ch = s[b-1];
  81. mp[ch].erase(b-1);
  82. char ch1 = 'a'+(c-1);
  83. mp[ch1].insert(b-1);
  84. }
  85. else{
  86. int cnt = 0;
  87. for(char j = 'a' ; j<='z' ; j++){
  88. auto it = mp[j].upper_bound((c-1));
  89. if(it==mp[j].begin()){
  90. continue;
  91. }
  92. else{
  93. it--;
  94. int r = *it;
  95. if(r>=(b-1)){
  96. cnt++;
  97. }
  98. }
  99. }
  100. ans.push_back(cnt);
  101. }
  102. }
  103. for(int i = 0 ; i<ans.size() ; i++){
  104. cout<<ans[i]<<" ";
  105. }
  106. cout<<endl;
  107. }
  108. signed main() {
  109. ios::sync_with_stdio(false); cin.tie(NULL);
  110. //int t;
  111. //cin >> t;
  112. //while (t--) {
  113. solve();
  114. //}
  115. return 0;
  116. }
  117.  
Success #stdin #stdout 0s 5312KB
stdin
abccbda
5
2 3 6
1 2 3
2 2 4
1 1 5
2 1 7
stdout
3 1 5