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  1. i=raw_input()
  2. if i[1]>"9":print"2CH4 + 4O2 > 4H2O + 2CO2"
  3. else:O=3*int(i[1:i.find('H')])+1;C=2*int(i[1:i.find('H')]);print"2"+i+" + "+`O`+"O2"+" > "+i[i.find('H'):]+"H2O"+ " + "+`C`+"CO2"
Success #stdin #stdout 0.01s 9016KB
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stdin
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C3H8
stdout
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2C3H8 + 10O2 > H8H2O + 6CO2
https://ideone.com/GZWCIF
language:
Python (cpython 2.7.16)
created:
8 years ago
visibility:
secret

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