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  1. import re
  2.  
  3. text = ("23,\"1,309\",0\n"
  4. 	"23,\"134,799\",2\n"
  5. 	",\"1,549,089\",0\n"
  6. 	"8908.89,\"27,989\",3")
  7. regex = r'"(?:\d+,)?\d+,\d+"'
  8. print(re.findall(regex, text))
Success #stdin #stdout 0.02s 9544KB
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stdin
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Standard input is empty
stdout
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['"1,309"', '"134,799"', '"1,549,089"', '"27,989"']
https://ideone.com/GVg1t9
language:
Python 3 (python  3.12)
created:
5 years ago
visibility:
secret

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