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  1. for n in range(1, 40000):
  2. 	if (1 + 2 ** (2 * n + 1)) % ((2 * n + 1) ** 2) == 0:
  3. 		print(n)
  4.  
Success #stdin #stdout 4.62s 27712KB
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https://ideone.com/GGijCL
language:
Python 3 (python  3.9.5)
created:
5 years ago
visibility:
public

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