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  1. import java.util.*;
  2. import java.lang.*;
  3. import java.io.*;
  4. import java.util.Scanner;
  5.  
  6. class Main
  7. {
  8. 	public static void main (String[] args) throws java.lang.Exception
  9. 	{
  10. 		int n, e, k=0, m, maxk = 0, maxn = 1000000000, p = 1;
  11. 		Scanner in = new Scanner(System.in);
  12. 		e = in.nextInt();
  13. 		while (e -- > 0) {
  14.         	n = in.nextInt();
  15. 			if (p <= n){
  16. 				m = n;
  17. 				k = 0;
  18. 				while ((n % 10) == 0) {
  19. 					//считает нули
  20. 					n = n / 10;
  21. 					k ++;
  22. 				}
  23. 				if (maxk < k) {
  24. 					maxn = m;
  25. 					maxk = k;
  26. 					p = 1;
  27. 					for (int i = 1; i < maxk; i ++) {
  28. 						p *= 10;
  29. 					}
  30. 				} else if (maxk == k) {
  31. 					if(maxn > m) maxn = m;
  32. 				}
  33. 			}
  34. 		}
  35. 		System.out.print(maxn);
  36. 	}
  37. }
Success #stdin #stdout 0.06s 2184192KB
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stdin
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4
100000
200000
500000
800000
stdout
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100000
https://ideone.com/G4W20j
Наиболее круглое число (java)
language:
Java (HotSpot 12)
created:
5 years ago
visibility:
secret

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