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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	int a1[] = {1, 2, 3, 4, 5, 6, 7, 8};
  5.     int a2[] = {1, 3, 5, 7};
  6.     printf("elements of a1 not present in a2:");
  7.     for (int i = 0; i < sizeof a1 / sizeof *a1; i++) {
  8.         int found = 0;
  9.         for (int j = 0; j < sizeof a2 / sizeof *a2; j++) {
  10.             if (a1[i] == a2[j]) { found = 1; break; }
  11.         }
  12.         if (!found) printf(" %d", a1[i]);
  13.     }
  14.     puts("");
  15. 	return 0;
  16. }
  17.  
Success #stdin #stdout 0s 9424KB
comments (?)
stdin
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Standard input is empty
stdout
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elements of a1 not present in a2: 2 4 6 8
https://ideone.com/FpvFKt
disjunction
language:
C (gcc 8.3)
created:
4 years ago
visibility:
secret

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