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  1. import re
  2. s= "the amount is 5/10 of the original. The #2 number should be extracted on the dd/yy"
  3. r = re.findall(r'[/#]\S+',s)
  4. print(r)              # => ['/10', '#2', '/yy']
  5. print(" ".join(r))    # => /10 #2 /yy
Success #stdin #stdout 0s 23288KB
comments (?)
stdin 
Standard input is empty
stdout 
['/10', '#2', '/yy']
/10 #2 /yy
https://ideone.com/FdzI5G
language:
Python (cpython 2.7.16)
created:
6 years ago
visibility:
secret

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