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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4.     long double factorialn, n, power, factoriald;
  5.     long double sum = 2;
  6.     factorialn = 1;
  7.     n = 10;
  8.     power = 2;
  9.     factoriald = 1;
  10.     for (int i = 1; i <= n; i++) {
  11.         factorialn *= i;
  12.         power *= 2;
  13.         for (int j = 2 * i; j <= 2 * i + 1; j++) {
  14.             factoriald *= j;
  15.         }
  16.         sum += factorialn * factorialn * power / factoriald;
  17.     }
  18.     printf("summa %1.16Lf\n", sum);
  19.     return 0;
  20. }
Success #stdin #stdout 0s 9424KB
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summa 3.1411060216013776
https://ideone.com/Fb8c88
language:
C (gcc 8.3)
created:
7 years ago
visibility:
secret

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