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  1. #include <stdio.h>
  2. #define N 2
  3.  
  4. void Gaussian_elimination(double a[N][N+1]){
  5.     int i,j,k;
  6.     double p,d;
  7.  
  8.     for (i = 0; i < N; i++) {
  9.         p = a[i][i];
  10.         for (j = 0; j < (N + 1); j++) {
  11.             a[i][j] = a[i][j] / p;
  12.         }
  13.         for (j = 0; j < N; j++) {
  14.             if (i != j) {
  15.                 d = a[j][i];
  16.                 for (k = i; k < (N + 1); k++) {
  17.                     a[j][k] = a[j][k] - d * a[i][k];
  18.                 }
  19.             }
  20.         }
  21.      }
  22. }
  23.  
  24. int main(void)
  25. {
  26.     // 連立方程式を表す係数行列
  27.     // x + y = 300
  28.     // 0.08x + 0.05y = 21
  29.     double a[N][N + 1] = {
  30.         {1.0, 1.0, 300},
  31.         {0.08, 0.05, 21}
  32.     };
  33.     char b[2][4] = {"x", "y"};
  34.     int i;
  35.  
  36.     // ガウスの消去法を使って連立方程式を解く
  37.     Gaussian_elimination(a); 
  38.  
  39.     // 結果を表示
  40.     for (i = 0; i < N; i++) {
  41.         printf("%s = %f\n", b[i], a[i][N]);
  42.     }
  43.  
  44.     return 0;
  45. }
  46.  
Success #stdin #stdout 0s 5288KB
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stdin
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Standard input is empty
stdout
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x = 200.000000
y = 100.000000
https://ideone.com/FLY5Tv
language:
C (gcc 8.3)
created:
74 days ago
visibility:
public

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