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  1. #include <stdio.h>
  2. int power(double x,int n){
  3.     int p=1;
  4.     int i;
  5.     for(i=1;i<=n;i++)
  6.     p=p*x;
  7.     return p;
  8. }
  9. int main(void) {
  10. 	double b,z;
  11.     int a;
  12.     scanf("%lf%d",&b,&a);
  13.     z=power(b,a);
  14.     printf("%lf的%d次放是:%lf",b,a,z);
  15. 	return 0;
  16. }
  17.  
Success #stdin #stdout 0s 5376KB
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stdin
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3.0 2
stdout
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3.000000的2次放是:9.000000
https://ideone.com/FAjrPR
language:
C (gcc 8.3)
created:
13 hours ago
visibility:
public

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