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  1. fun binarySearch(array: List<Int>, number: Int, left: Int, right: Int): Int {
  2.   if(left == right && array[left] == number) {
  3.     return left
  4.   }
  5.   else if (left >= right) {
  6.     return -1
  7.   }
  8.  
  9.   val middle = (left + right) / 2
  10.  
  11.   if (number < array[middle]) {
  12.     return binarySearch(array, number, left, middle)
  13.   } else if (number > array[middle]) {
  14.     return binarySearch(array, number, middle + 1, right)
  15.   } else {
  16.     return middle
  17.   }
  18. }
  19.  
  20. fun main() {
  21.   val array = listOf(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)
  22.   val number = 8
  23.  
  24.   val index = binarySearch(array, number, 0, array.count())
  25.  
  26.   if (index == -1) {
  27.     println("Szukanej liczby nie ma na liscie")
  28.   } else {
  29.     println("Szukana liczba znajduje sie pod indeksem $index")
  30.   }
  31. }
Success #stdin #stdout 0.1s 39584KB
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Szukana liczba znajduje sie pod indeksem 7
https://ideone.com/F0QMN2
Binary search recursive
language:
Kotlin (kotlin 1.3.21)
created:
2 years ago
visibility:
public

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