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#include <stdio.h>
#include <stddef.h>
#define LEN 2
 
void foo(int* a[][10], size_t len) {
	printf("%s\n", "successfully called foo.");
}
 
int main(void) {
 
	// a is an LEN-array of an 10-array of (int *)
	int *a[LEN][10] = {{0}};
	// but the identifier `a` will decay to be a pointer of type int*[10]
 
	// p1 is a pointer to an 10-array of (int *)
	int *(*p1)[10] = 0;
 
	foo(a, LEN);
	foo(&a, LEN);
 
	return 0;
}
 

prog.cpp: In function ‘int main()’:
prog.cpp:20:13: error: cannot convert ‘int* (*)[2][10]’ to ‘int* (*)[10]’ for argument ‘1’ to ‘void foo(int* (*)[10], size_t)’
  foo(&a, LEN);
             ^

Standard output is empty