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  1. #include <stdio.h>
  2.  
  3. void cal(int x, int y, int *sum, int *diff, int *mul, int *mod) {
  4.     *sum = x + y;
  5.     *diff = (x > y) ? (x - y) : (y - x);  // 差の絶対値を格納
  6.     *mul = x * y;
  7.     *mod = x / y;  // 商（小数点以下を切り捨て）
  8. }
  9.  
  10. int main(void) {
  11.     int x = 10, y = 3;
  12.     int sum, diff, mul, mod;
  13.  
  14.     cal(x, y, &sum, &diff, &mul, &mod);
  15.  
  16.     printf("%dと%dの和は%d\n", x, y, sum);
  17.     printf("%dと%dの差は%d\n", x, y, diff);
  18.     printf("%dと%dの積は%d\n", x, y, mul);
  19.     printf("%dと%dの商は%d\n", x, y, mod);
  20.  
  21.     return 0;
  22. }
  23.  
Success #stdin #stdout 0s 5284KB
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Standard input is empty
stdout
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10と3の和は13
10と3の差は7
10と3の積は30
10と3の商は3
https://ideone.com/EnEFjb
language:
C (gcc 8.3)
created:
13 hours ago
visibility:
public

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