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  1. #include <iostream>
  2. using namespace std;
  3.  
  4. int main() {
  5.     int n, m, mt[1001][1001];
  6.     cin >> n >> m;
  7.     for (int i = 1; i <= n; ++i) {
  8.         for (int j = 1; j <= m; ++j) {
  9.             cin >> mt[i][j];
  10. 		}
  11. 	}
  12.     int k, wanted_value;
  13.     cin >> k;
  14.     for (int query = 1; query <= k; query++) {
  15.         cin >> wanted_value;
  16.         int found = 0;
  17.         for (int i = 1; i <= n && !found; ++i) {
  18.             if (mt[i][1] <= wanted_value && wanted_value <= mt[i][m]) {
  19.                 int left_col = 1, right_col = m;
  20.                 while (left_col < right_col) {
  21. 					int mid_col = (left_col + right_col) / 2;
  22. 					if (mt[i][mid_col] < wanted_value) {
  23. 						left_col = mid_col + 1;
  24. 					} else {
  25. 						right_col = mid_col;
  26. 					}
  27. 				}
  28. 				if (mt[i][left_col] == wanted_value) {
  29. 					found = 1;
  30. 				}
  31.             }
  32.         }
  33.         if (found) {
  34.             cout << "DA" << '\n';
  35.         } else {
  36.             cout << "NU" << '\n';
  37.         }
  38.     }
  39.     return 0;
  40. }
  41.  
Success #stdin #stdout 0.01s 5268KB
comments (?)
stdin
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5 3 1 2 3 2 5 6 5 6 7 77 88 9 10 2 5 9 2 4 10 7 5 77 11 88 55
stdout
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DA
NU
NU
DA
DA
NU
NU
NU
NU
https://ideone.com/Dnlpe2
language:
C++ (gcc 8.3)
created:
119 days ago
visibility:
public

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