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  1. #include<iostream>
  2. #include<cmath>
  3. #include<complex>
  4. using namespace std;
  5.  
  6. int main() {
  7. 	//This program will take a quadratic in the form Ax^2+Bx+c and solve for the roots of the quadratic using the quadratic formula
  8. 	//Quad Form: -b+-sqrt((b^2-4ac)/(2a))
  9. 	//Working on adding imaginary(i) numbers
  10. 	//(2,1) in complex c++ is the same as 2+i in math
  11. 	// Lots of help in complex c++ in this thread {http://w...content-available-to-author-only...b.com/software-development/cpp/threads/311699}
  12.  
  13. 	double a, b, c;
  14. 	double Sol1, Sol2;
  15. 	complex<double> cSol1, cSol2, discr;
  16.  
  17.  
  18. 	cout << "Enter A,B, and C. From the general form of a quadratic. Ax^2+Bx+c";
  19. 	cout << "\nEnter A  ";
  20. 	cin >> a;
  21. 	cout << "\nEnter B  ";
  22. 	cin >> b;
  23. 	cout << "\nEnter C  ";
  24. 	cin >> c;
  25.  
  26. 	if (a==0){
  27. 	    cout<< "Not a Quadratic\n";
  28. 	    }
  29.  
  30.  
  31. 	else if ((b*b-4*a*c) < 0) {
  32. 		cout << "\nImaginary Roots";
  33. 		discr =sqrt(complex<double>(b*b-4*a*c));
  34. 		complex<double> cSol1= ((-1*b)-discr)/(2*a);
  35. 	 	complex<double> cSol2= ((-1*b)+discr)/(2*a);
  36.  
  37. 		cout << "\nThe solutions are x = " << cSol1;
  38. 		cout << "\nAnd x = " << cSol2 << endl;
  39.  
  40. 		}
  41.  
  42. 	else {
  43.  
  44. 	Sol1=sqrt(pow(b , 2)-(4*a*c))-(b*-1);
  45. 	Sol1= (Sol1)/(2*a);
  46. 	Sol2=((-1)*sqrt(pow(b, 2)-(4*a*c)))-(b*-1);
  47. 	Sol2=(Sol2)/(2*a);
  48.  
  49. 	cout <<"\n The Solutions are x = " << Sol1;
  50. 	cout <<"  And x = " << Sol2 << endl;
  51. }
  52.  
  53. 	return 0;
  54. 	}
Success #stdin #stdout 0s 2860KB
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Standard input is empty
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Enter A,B, and C. From the general form of a quadratic. Ax^2+Bx+c
Enter A  
Enter B  
Enter C  
Imaginary Roots
The solutions are x = (-0.502345,-0)
And x = (-0.502345,0)
https://ideone.com/DURRq
language:
C++ (gcc 8.3)
created:
14 years ago
visibility:
public

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