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  1. #include <stdio.h>
  2. //a{n+1} = -2a{n} + 4, a{0}=2(再帰なし版)
  3. int main(void) {
  4.     int n;
  5.     int an = 2;
  6.     scanf("%d",&n);
  7.     for(int i = 0;i<n;i++){
  8.          an = -2*an + 4;
  9.          printf("a%d = %d\n",i+1,an);
  10.     }
  11.     printf("数列a%dの値は%d\n", n, an);
  12.  
  13. 	return 0;
  14. }
  15.  
  16.  
Success #stdin #stdout 0s 5316KB
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stdin
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5
stdout
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a1 = 0
a2 = 4
a3 = -4
a4 = 12
a5 = -20
数列a5の値は-20
https://ideone.com/CtbsjL
language:
C (gcc 8.3)
created:
4 days ago
visibility:
public

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