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  1. df <- data.frame(name=c("Hans", "Dieter", "Peter"), age=c(25,26,27))
  2. df
  3. df[] <- lapply(df, gsub, pattern='a', replacement="e")
  4. df
Success #stdin #stdout 0.26s 39952KB
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Standard input is empty
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    name age
1   Hans  25
2 Dieter  26
3  Peter  27
    name age
1   Hens  25
2 Dieter  26
3  Peter  27
https://ideone.com/C2So6p
language:
R (R 3.5.2)
created:
4 years ago
visibility:
secret

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