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  1.    f= @(n)any([sum(n);sum(n')]-100,2)
  2.  
  3.     f(100)
  4.     f(42)
  5.     f([4,8,15; 16,23,42; 80,69,43])
  6.     f([99,1;2,98])
  7.     f([1,2,3,4;5,6,7,8;9,10,11,12;13,14,15,16])
Success #stdin #stdout 0.3s 121792KB
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Standard input is empty
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f =

@(n) any ([sum(n); sum(n')] - 100, 2)

ans =

   0
   0

ans =

   1
   1

ans =

   0
   1

ans =

   1
   0

ans =

   1
   1
https://ideone.com/ByF5r1
language:
Octave (octave 4.4.1)
created:
7 years ago
visibility:
public

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