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  1. import re
  2. str_1= 'hoooowe'
  3. pattern = re.compile(r'([aeiouy])\1{2}')
  4. print([x.group() for x in pattern.finditer(str_1)])
  5.  
Success #stdin #stdout 0.01s 27712KB
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Standard input is empty
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['ooo']
https://ideone.com/BfpkPI
language:
Python 3 (python  3.9.5)
created:
5 years ago
visibility:
secret

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