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  1. h = [
  2. 	{name: 'Vasya', apples: 2, bananas: 4},
  3. 	{name: 'Sasha', apples: 0, bananas: 5},
  4. 	{name: 'Misha', apples: 1, bananas: 0},
  5. 	{name: 'Petya', apples: 2, bananas: 6},
  6. 	{name: 'Dasha', apples: 3, bananas: 0}
  7. ]
  8.  
  9. ignore_keys = %i[name]
  10.  
  11. h.each do |e|
  12. 	k,v = e.reverse_each.find do |k,v|
  13. 		next if ignore_keys.include? k
  14.  
  15. 		v != 0
  16. 	end
  17. 	puts "#{e[:name] } - #{k} : #{v}"
  18. end
Success #stdin #stdout 0.01s 6296KB
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Vasya - bananas : 4
Sasha - bananas : 5
Misha - apples : 1
Petya - bananas : 6
Dasha - apples : 3
https://ideone.com/BHw4lX
language:
Ruby (ruby 2.5.5)
created:
3 years ago
visibility:
public

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